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[Rods2]

There is no way of calculating it unless you assume they are perfectly mixed, so is this a given assumption?

Likewise you would also have to assume that all of the wine was poured from the red glass and the tumbler, so they were both completely dry.

[bigegg]

Ffs. Fill the tumbler. When its full, stop pooring. Idiots!

I blame the wine 

[bigegg]

In the original question you said "fill from red wine glass and poor it into the white wine"
NOT the "white wine glass"

 

and besides, a wine glass is NEVER filled to the brim, so that the aroma has chance to develop above the liquid.

[al brown]

No complicated maths, both glasses have the same amount of wine in them, 1 tumbler removed from glass one and then replaced, therefore each has as much of the other colour in it. If one had more than the other it would have gained some volume. Ratio makes no difference as far as I can see.

[chrisgixer]

No complicated maths, both glasses have the same amount of wine in them, 1 tumbler removed from glass one and then replaced, therefore each has as much of the other colour in it. If one had more than the other it would have gained some volume. Ratio makes no difference as far as I can see.

See, that's my point.

Take a tumbler of red and poor it into the white. This means you've pored a tumbler full of 100% red into the whit glass.

Now, you have a pink "Rose" white wine glass. Yes? So there MUST be some red in the tumbler when returning the same amount of fluid from the white glass to the red.

Therefor there MUST be more red wine in the white glass than there is white wine in the red glass.

Yes the total volume is the same, but that is NOT the question. That being, after pooring a tumbler of red into the white, THEN poring a tumbler from the white(pink) back to the red, is the more red in the white, or more white in the red...?

Just to repeat, they said the answer was, as you say, the same. Same total volume yes. But not the same ratio. Proof being in the colour.

[Entwood]

If the tumbler is the same size as the CONTENT of the wine glass then ALL the red goes into the white then half the rose goes back into the red glass. It is NOT the size of the wine glass that matters, but the amount of wine in it at the start .....   

[chrisgixer]

If the tumbler is the same size as the CONTENT of the wine glass then ALL the red goes into the white then half the rose goes back into the red glass. It is NOT the size of the wine glass that matters, but the amount of wine in it at the start .....   

It's not. Tumbler is smaller. Wine glass is bigger.

Tumbler being about the size of a sherry glass. Or roughly 10% the volume of the wine glass.

[chrisgixer]

Actually. The tumbler is not important.

Just poring 10% into one! then back again. Would give the same result. Provided the amount was accurate. (Hence the tumbler)

The result being, which ever is pored first looses most, and must receive less of its own colour back. As its now mixed. Even though the total volume will be the same when finished.

[PhilRich]

Judging by the state of your spelling as this thread gets longer Chris, there can't be much left of either Red or bloody White! Or are you seeing the world through Rosé tinted glasses

[al brown]

If both glasses have the same amount of wine at the end then however much red had gone into the white must be the same as white into the red. When I said ratio doesn't matter I meant that the ratio will be different between the 2 glasses, ie opposite. If at the end there is only 60% of the red left in the red glass then there must be 40% white and vice versa, 20% red left then it's 80% white and vice versa.

[chrisgixer]

If both glasses have the same amount of wine at the end then however much red had gone into the white must be the same as white into the red. When I said ratio doesn't matter I meant that the ratio will be different between the 2 glasses, ie opposite. If at the end there is only 60% of the red left in the red glass then there must be 40% white and vice versa, 20% red left then it's 80% white and vice versa.

If the first tumbler pored has 100% red, then the second can not possibly have 100% white. Therefor, there's more red in the white glass. No?

[MR MISTER]

If both glasses have the same amount of wine at the end then however much red had gone into the white must be the same as white into the red. When I said ratio doesn't matter I meant that the ratio will be different between the 2 glasses, ie opposite. If at the end there is only 60% of the red left in the red glass then there must be 40% white and vice versa, 20% red left then it's 80% white and vice versa.

If the first tumbler pored has 100% red, then the second can not possibly have 100% white. Therefor, there's more red in the white glass. No?

You do know that people like to wind you up over tyres, wine glasses and the like...........don't you? 

[chrisgixer]

Judging by the state of your spelling as this thread gets longer Chris, there can't be much left of either Red or bloody White! Or are you seeing the world through Rosé tinted glasses

Always

[chrisgixer]

If both glasses have the same amount of wine at the end then however much red had gone into the white must be the same as white into the red. When I said ratio doesn't matter I meant that the ratio will be different between the 2 glasses, ie opposite. If at the end there is only 60% of the red left in the red glass then there must be 40% white and vice versa, 20% red left then it's 80% white and vice versa.

If the first tumbler pored has 100% red, then the second can not possibly have 100% white. Therefor, there's more red in the white glass. No?

You do know that people like to wind you up over tyres, wine glasses and the like...........don't you? 

You don't know the answer either then Esta.

[MR MISTER]

If both glasses have the same amount of wine at the end then however much red had gone into the white must be the same as white into the red. When I said ratio doesn't matter I meant that the ratio will be different between the 2 glasses, ie opposite. If at the end there is only 60% of the red left in the red glass then there must be 40% white and vice versa, 20% red left then it's 80% white and vice versa.

If the first tumbler pored has 100% red, then the second can not possibly have 100% white. Therefor, there's more red in the white glass. No?

You do know that people like to wind you up over tyres, wine glasses and the like...........don't you? 

You don't know the answer either then Esta.

The correct answer was given on the TV programme, I'm assuming. Think I'd trust their maths against yours most days.