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Author Topic: Schools of hard sums. Right or wrong?  (Read 3328 times)

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al brown

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Re: Schools of hard sums. Right or wrong?
« Reply #30 on: 17 November 2013, 21:20:38 »

Second tumbler ratio doesn't matter as long as both glasses have the same volume left at the end. You can ignore the ratio, it just doesn't matter. All that matters is the fact both glasses have the same volume at the end. Therefore whatever % red is in one glass must be the same as white in the other.
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chrisgixer

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Re: Schools of hard sums. Right or wrong?
« Reply #31 on: 17 November 2013, 21:24:54 »

If both glasses have the same amount of wine at the end then however much red had gone into the white must be the same as white into the red. When I said ratio doesn't matter I meant that the ratio will be different between the 2 glasses, ie opposite. If at the end there is only 60% of the red left in the red glass then there must be 40% white and vice versa, 20% red left then it's 80% white and vice versa.


If the first tumbler pored has 100% red, then the second can not possibly have 100% white. Therefor, there's more red in the white glass. No?
You do know that people like to wind you up over tyres, wine glasses and the like...........don't you?  ;D
You don't know the answer either then Esta. ::) ;)
The correct answer was given on the TV programme, I'm assuming. Think I'd trust their maths against yours most days. ;D
So would I, normally. Except there's NO MATHS INVOLVED. ;D

Oh well. At least you and I are as thick as each other. Clearly.

No wait, I'm putting myself down here ;D
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Entwood

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Re: Schools of hard sums. Right or wrong?
« Reply #32 on: 17 November 2013, 21:26:44 »

to explain it mathematically .. and using simple numbers .. If the wine glass holds 100 ml and the tumbler holds 20 ml ..

both wine glasses intially hold 100 ml red / white respectively.

take 20 ml red out of the red glass - it holds 80 ml now

pour the 20 ml into the 100 white .. you have 120 ml of which 20 is red, so is 100 is white .. so it is 83% white and 17% red  (100/120 * 100 white 20/120 * 100 red)

pour 20 ml out of that glass into the tumbler .. what REMAINS in the "white glass" is still 83% white 17% red

the 20 ml in the tumbler is also 83% / 17% so contains 17 ml white and 3 ml red

pour that into the 80 ml red and you have

80 + 3 ml red - 83 + 17 ml white ... so 83% red and 17% white

so there is the a same amount of red wine in the white glass as there is white wine in the red glass .. which is what the original question asks if you read it properly .. it never says the amount of red and white is the same

"Is there more red in the white glass? Or more white in the red glass?"
« Last Edit: 17 November 2013, 21:28:44 by Entwood »
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bigegg

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Re: Schools of hard sums. Right or wrong?
« Reply #33 on: 17 November 2013, 21:31:11 »


so there is the a same amount of red wine in the white glass as there is white wine in the red glass .. which is what the original question asks if you read it properly .. it never says the amount of red and white is the same

"Is there more red in the white glass? Or more white in the red glass?"

You can't just go around reading the question properly, and then making rational statements based on it.
This is the *internet*
 ::)

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chrisgixer

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Re: Schools of hard sums. Right or wrong?
« Reply #34 on: 17 November 2013, 21:32:31 »

So a ratio of 4:1 at all times.
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chrisgixer

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Re: Schools of hard sums. Right or wrong?
« Reply #35 on: 17 November 2013, 21:33:14 »

So a ratio of 4:1 at all times.

(Waits for a smart arse reply from Esta, like he knew all along. ;D)
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MR MISTER

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Re: Schools of hard sums. Right or wrong?
« Reply #36 on: 17 November 2013, 21:33:28 »


so there is the a same amount of red wine in the white glass as there is white wine in the red glass .. which is what the original question asks if you read it properly .. it never says the amount of red and white is the same

"Is there more red in the white glass? Or more white in the red glass?"

You can't just go around reading the question properly, and then making rational statements based on it.
This is the *internet*
 ::)
Quite right Humpty  :y
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Andy B

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Re: Schools of hard sums. Right or wrong?
« Reply #37 on: 17 November 2013, 21:39:54 »


Just drink both glasses .......  ::) ::)
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chrisgixer

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Re: Schools of hard sums. Right or wrong?
« Reply #38 on: 17 November 2013, 21:41:10 »


Just drink both glasses .......  ::) ::)

In the school of hard drinking, yes, Mr B. ;)
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al brown

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Re: Schools of hard sums. Right or wrong?
« Reply #39 on: 17 November 2013, 21:46:14 »

So a ratio of 4:1 at all times.
Ratio will depend on how big the tumbler is, point being the ratio in one glass will be opposite the other, ie same amount of red in the white glass as white in the red.
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al brown

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Re: Schools of hard sums. Right or wrong?
« Reply #40 on: 17 November 2013, 21:54:31 »

Have just checked and it works with vodka and a mixer too  ;D
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chrisgixer

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Re: Schools of hard sums. Right or wrong?
« Reply #41 on: 17 November 2013, 22:09:00 »

Have just checked and it works with vodka and a mixer too  ;D

Anything goes in the name of research. :y ;D
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