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[PaulW]

Here's a complex (or simple one to some) query...

You have 2 points in a 3D space.

Point A is located at XYZ (-10, -7, 4)
Point B is located at XYZ (-10. -4, 2)

Distance between points is worked out by SQRT((Xa*Xb) + (Ya*Yb) + (Za*Zb)) which works out at 11.66

What I want to do now is work out the new position of Point B if its rotated around Point A by:
X - 30deg
Y - 20deg
Z - 40deg

Hope that makes sense...

[Taxi_Driver]

Here's a complex (or simple one to some) query...

You have 2 points in a 3D space.

Point A is located at XYZ (-10, -7, 4)
Point B is located at XYZ (-10. -4, 2)

Distance between points is worked out by SQRT((Xa*Xb) + (Ya*Yb) + (Za*Zb)) which works out at 11.66

What I want to do now is work out the new position of Point B if its rotated around Point A by:
X - 30deg
Y - 20deg
Z - 40deg

Hope that makes sense...

Its 42 mate  

[PaulW]

Here's a complex (or simple one to some) query...

You have 2 points in a 3D space.

Point A is located at XYZ (-10, -7, 4)
Point B is located at XYZ (-10. -4, 2)

Distance between points is worked out by SQRT((Xa*Xb) + (Ya*Yb) + (Za*Zb)) which works out at 11.66

What I want to do now is work out the new position of Point B if its rotated around Point A by:
X - 30deg
Y - 20deg
Z - 40deg

Hope that makes sense...

Its 42 mate  

  if only  

All I need is the formula to work this out... not the actual result...

Google returns bugger all which is useful...

[Leomas]

Can you not simply do vector sums using the initial distance between A and B and each angle in turn?