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Author Topic: Schools of hard sums. Right or wrong?  (Read 3373 times)

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chrisgixer

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Schools of hard sums. Right or wrong?
« on: 17 November 2013, 15:24:17 »

Dara O'Briens schools of hard sums. What have I missed?

A glass of white wine. A glass of Red wine.

Take a small tumbler, fill from red wine glass and poor it into the white wine.


Then take fill the tumbler from the white wine glass and poor it back into the red glass.



Question is. Is the more red in the white glass? Or more white in the red glass?



Answer. Its the same.



Are they right?

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chrisgixer

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Re: Schools of hard sums. Right or wrong?
« Reply #1 on: 17 November 2013, 15:45:59 »

10 views and no replies.

Pussies. ;D
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Field Marshal Dr. Opti

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Re: Schools of hard sums. Right or wrong?
« Reply #2 on: 17 November 2013, 15:52:49 »

I've always bin no good at maffs. :)
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Varche

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Re: Schools of hard sums. Right or wrong?
« Reply #3 on: 17 November 2013, 16:30:14 »

My gut feeling was the diluted wine out of second glass would make the red wine less in the first glass.

Then I worked an example and assumed the tumbler holds exactly half the wine glass, the red wine was Rioja and the White a crisp Chardonnay and concluded:

Red wine glass has two thirds red and one third white and white wine glass has two thirds white one third red.

I might be wrong. I might try a practical test tonight when I have my curry. ;D ;D
 
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chrisgixer

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Re: Schools of hard sums. Right or wrong?
« Reply #4 on: 17 November 2013, 17:17:45 »

To me, it's what is in the tumbler as it crosses over.

The first pass, holds pure red wine, as it goes into the white wine glass.


The second pass, holds a combination of both, as it replaces the same amount if fluid back into the red.

There in lies the difference. IMO.

Where as the programme states that the amount of fluid is the same in each. Which it is. So the amount of red and white must be the same. Not so.

I think the programme is wrong. But then I'm shit at maths. ;D
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Taxi_Driver

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Re: Schools of hard sums. Right or wrong?
« Reply #5 on: 17 November 2013, 18:17:00 »

Dara O'Briens schools of hard sums. What have I missed?

A glass of white wine. A glass of Red wine.

Take a small tumbler, fill from red wine glass and poor it into the white wine.


Then take fill the tumbler from the white wine glass and poor it back into the red glass.



Question is. Is the more red in the white glass? Or more white in the red glass?



Answer. Its the same.



Are they right?

Well, thats going to make bloody mess to start with....all over the floor/carpet  ::)

How can you add more wine to glass of wine  ::) :D (A glass of wine, to me, means its full)
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Seth

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Re: Schools of hard sums. Right or wrong?
« Reply #6 on: 17 November 2013, 18:20:58 »

[quote author=Taxi Driver link=topic=119396.msg1515701#msg1515701 date=1384712220
Well, thats going to make bloody mess to start with....all over the floor/carpet  ::)

How can you add more wine to glass of wine  ::) :D (A glass of wine, to me, means its full)
[/quote]

Exactly! ;)

Someone ain't throwin' straight dice here ...  ::)
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MR MISTER

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Re: Schools of hard sums. Right or wrong?
« Reply #7 on: 17 November 2013, 18:22:45 »

I'm guessing with Gixer bein illiterate an all, he ain't explained it right. ;D
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Seth

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Re: Schools of hard sums. Right or wrong?
« Reply #8 on: 17 November 2013, 18:24:55 »

I'm guessing with Gixer bein illiterate an all, he ain't explained it right. ;D

... like a piece of da jigsaw's missin' ???
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MR MISTER

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Re: Schools of hard sums. Right or wrong?
« Reply #9 on: 17 November 2013, 18:31:24 »

I'm guessing with Gixer bein illiterate an all, he ain't explained it right. ;D

... like a piece of da jigsaw's missin' ???
A perfect description of the boy  ;D ;D
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Varche

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Re: Schools of hard sums. Right or wrong?
« Reply #10 on: 17 November 2013, 18:38:02 »

While we wait for Chris, I think I have invented a new wine.

I am going to call it Rose (with an accent on that last e, pronounced Rose ehh). Not bad either. Curry will be ready in 30 minutes time :y
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bigegg

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Re: Schools of hard sums. Right or wrong?
« Reply #11 on: 17 November 2013, 18:56:21 »

Dara O'Briens schools of hard sums. What have I missed?

A glass of white wine. A glass of Red wine.

Take a small tumbler, fill from red wine glass and poor it into the white wine.


Then take fill the tumbler from the white wine glass and poor it back into the red glass.



Question is. Is the more red in the white glass? Or more white in the red glass?



Answer. Its the same.



Are they right?

Both the same - none in either.

hic.
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bigegg

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Re: Schools of hard sums. Right or wrong?
« Reply #12 on: 17 November 2013, 19:55:34 »

serious answer.

let a=capacity of wine glass
let b= capacity of tumbler.

step 1.
We have A ml white wine in glass x
We have A ml of red wine in glass y

Step 2.
Glass x now holds A ml of white wine + B ml of red wine.
glass y now holds A-B ml of red wine.

Step 3
We pour B ml of the mixed wine back into glass y

so glass y now holds ((A-B) + (BxB/A+B))ml of red wine PLUS (AxB/A+B)ml white wine.
Glass X now holds (A-B)ml mixture, of which (B/A+B) is white wine.


so glass Y has (AxB/A+B) of white
glass X has (A-B)(B/A+B) of white

AB/A+B is not the same as (AB-B2)/A+B except when B=0, so therefore, the question to the question, *as stated* is:
NO, they don't hold the same amount of white wine
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chrisgixer

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Re: Schools of hard sums. Right or wrong?
« Reply #13 on: 17 November 2013, 19:57:02 »

Ffs. Fill the tumbler. When its full, stop pooring. Idiots! ;D
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chrisgixer

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Re: Schools of hard sums. Right or wrong?
« Reply #14 on: 17 November 2013, 19:58:38 »

serious answer.

let a=capacity of wine glass
let b= capacity of tumbler.

step 1.
We have A ml white wine in glass x
We have A ml of red wine in glass y

Step 2.
Glass x now holds A ml of white wine + B ml of red wine.
glass y now holds A-B ml of red wine.

Step 3
We pour B ml of the mixed wine back into glass y

so glass y now holds ((A-B) + (BxB/A+B))ml of red wine PLUS (AxB/A+B)ml white wine.
Glass X now holds (A-B)ml mixture, of which (B/A+B) is white wine.


so glass Y has (AxB/A+B) of white
glass X has (A-B)(B/A+B) of white

AB/A+B is not the same as (AB-B2)/A+B except when B=0, so therefore, the question to the question, *as stated* is:
NO, they don't hold the same amount of white wine

Bigegg. If we need to tell people to stop pooring when a glass is full, we have no chance. ;D
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